Initially, 50.0 g iron(iii) chloride is present. what amount of fecl3 is this, in moles?

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01-02-2018
Chemistry

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Initially, 50.0 g iron(iii) chloride is present. what amount of fecl3 is this, in moles?

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jamuuj jamuuj · Answer 1 · 2018-02-10T10:39:48+01:00

jamuuj jamuuj

10-02-2018

One mole of a compound contains the mass equivalent to the molecular mass or relative formula mass of the compound.
1 mole of iron iii chloride contains a mass of 162.2 g.
Therefore, 50 g will contain 50 g/162.2 g = 0.3083 moles
= 0.3083 moles of Fe2Cl3

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