Seudónimo
Seudónimo
03-05-2017
Mathematics
contestada
what is the answer to this problem.
Respuesta :
BeautifulAfflictions
BeautifulAfflictions
03-05-2017
2y^2 - y - 1 = 0
(2y + 1) (y - 1) = 0
2y + 1 = 0 or y - 1 = 0
y = -1/2 or y = 1
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Аноним
Аноним
03-05-2017
When you factor this, you should get ( y - 1 )( 2y + 1 ) One of these inside the parenthesis has to equal 0, so the answer is either 1 or -1/2.
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