I'm going to use "x" because the program lets me put in exponents.
4[tex] x^{2} [/tex]-6x+2+3[tex] x^{2} [/tex]-1 7[tex] x^{2} [/tex]-6a-1 Then factor (7x+1)(x-1) Set each to 0 to solve for x x-1=0 is x=1 7x+1=0 7x=-1 x=[tex] \frac{-1}{7} [/tex] So your answers are x=1 and x=[tex] \frac{-1}{7} [/tex]
