The given slope is:
[tex]m=-6[/tex]And the point:
[tex](-8,8)[/tex]we label the coordinates as follows:
[tex]\begin{gathered} x_1=-8 \\ y_1=8 \end{gathered}[/tex]And now, we use the slope-point formula, which is:
[tex]y-y_1=m(x-x_1)[/tex]substituting the known values of slope m and the point:
[tex]y-8=-6(x-(-8))[/tex]We need to solve this for y to find the slope intercept form (which is y=mx+b):
[tex]\begin{gathered} y-8=-6(x+8) \\ y-8=-6x-48 \\ y=-6x-48+8 \\ y=-6x-40 \end{gathered}[/tex]The slope-intercept form is:
y = -6x - 40
