JuliyanB576896 JuliyanB576896

03-11-2022
Mathematics

contestada

Differentiate. f(x) = (4x2 - 8) - (1 + 4x3) f'(x) = 32x(4x2 - 8) 3 - 12x2(1 + 4x3,4 f'(x) = 32x(4x2 - 8) 3 - 60x?(1 + 4x3,4 f'(x) = (32x-8)(4x2 - 8)3 - (1 + 60x?)(1 + 4x334 f'(x) = 4(4x2 - 8) 3 - 5(1 +4x3)4

Differentiate fx 4x2 8 1 4x3 fx 32x4x2 8 3 12x21 4x34 fx 32x4x2 8 3 60x1 4x34 fx 32x84x2 83 1 60x1 4x334 fx 44x2 8 3 51 4x34 class=

Respuesta :

GarciaS568539 GarciaS568539

03-11-2022

we have

f(x)=(4x2-8)^4-(1+4x^3)^5

so

f'(x)=4(4x^2-8)^3(8x)-5(1+4x^3)^4(12x^2)

f'(x)=32x(4x^2-8)-60x^2(1+4x^3)^4

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