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02-01-2017
Mathematics

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What is the average rate of change of the function f(x)=5(2)x from x = 1 to x = 5?
P.S. On the equation, the second x is in the squared position.

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surjithayer surjithayer

02-01-2017

rate of change[tex]= \frac{f(5)-f(1)}{5-1} f(x)=5(2)x^2 f(5)=5(2)5^2=10*25=250 f(1)=5(2)1^2 [/tex]
[tex]rate of change= \frac{250-10}{5-1} = \frac{240}{4} =60[/tex]

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