kariukiphilip629
kariukiphilip629 kariukiphilip629
  • 03-04-2021
  • Physics
contestada

А masd
Of 500kg a raised to a height of 6m In 30s
Find (a) Workdone .​

Respuesta :

ukeshmainali30
ukeshmainali30 ukeshmainali30
  • 03-04-2021

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

Answer Link

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