tanatodorova8 tanatodorova8

03-01-2021
Mathematics

contestada

[tex]( {x}^{2} - 3x) \sqrt{ {x}^{2} + 5x + 4 } = 0[/tex]

Respuesta :

Аноним Аноним

03-01-2021

Answer:

x={-4,-1,0,3}

Step-by-step explanation:

(x²-3x)√x²+5x+4=0

x(x-3)=0

√x²+5x+4=0

x(x-3)=0

x=0

x-3=0

x=3

√x²+5x+4=0

x²+5x+4=0 (square both sides)

x²+4x+x+4=0

x(x+4)+1(x+4)=0

(x+4)(x+1)=0

x+1=0

x+4=0

x=-1

x=-4

Answer Link

lee08989 lee08989

03-01-2021

Answer:

there is is

Step-by-step explanation:

for x^2-3x=0

x=0 or x=3

Ver imagen lee08989

Answer Link

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