benjamin9651
benjamin9651 benjamin9651
  • 01-09-2020
  • Mathematics
contestada

Given that sin(90 -5ϴ) = Cos(180 - ϴ), Find the value of ϴ
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Hrishii
Hrishii Hrishii
  • 01-09-2020

Answer:

30°

Step-by-step explanation:

[tex] \because \: \sin(90 \degree - \theta) = \cos \theta \\ \therefore \: \sin(90 \degree - 5 \theta) = \cos 5\theta....(1) \\ \\ \sin(90 \degree - 5 \theta) = \cos(180 \degree - \theta)...(2) \\ from \: (1) \: and \: (2) \\ \cos 5\theta = \cos(180 \degree - \theta) \\ 5 \theta = 180 \degree - \theta \\ 5 \theta + \theta= 180 \degree \\ 6\theta= 180 \degree \\ \theta = \frac{180 \degree}{6} \\ \\ \huge \red{ \boxed{\theta = 30 \degree}}[/tex]

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