zawnghkawng3981 zawnghkawng3981
  • 04-08-2020
  • Mathematics
contestada

Let $x=5$, $y=\frac{3}{4}$, and $z=-\frac{1}{7}$. What is $\frac{xz}{y}?$

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 06-08-2020

Answer:

-20/21

Step-by-step explanation:

Given x = 5, y = 3/4 and z = -1/7, 2=we are to calculate [tex]\frac{xz}{y}[/tex]. Substituting the value of x, y and z into the expression will give;

[tex]= \frac{xz}{y}\\\\ \frac{5(-1/7)}{3/4} \\= \frac{-5/7}{3/4}\\\\= \frac{-5}{7} * \frac{4}{3}\\ \\ = \dfrac{-20}{21}\\[/tex]

Hence the value of the expression is -20/21

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