Respuesta :

wegnerkolmp2741o

Answer:

(2y+3)(y^2+7)

Step-by-step explanation:

2y^3  + 3y^2        + 14y +21

Factory^2 from the first group and    7 from the second group

y^2(2y+3)     + 7(2y+3)

Factor out (2y+3)

(2y+3)(y^2+7)