The length of rectangle is 15 feet and width of rectangle is 7 feet
Solution:
Let "a" be the width of rectangle
Given that, length of rectangle is 1 foot more than twice the width
Therefore, we get
length = 1 + twice the width
length = 1 + 2a ------ eqn 1
Given that perimeter is 44 feet
The perimeter of rectangle is given as:
Perimeter = 2(length + width)
44 = 2(1 + 2a + a)
44 = 2(1+3a)
22 = 1 + 3a
3a = 22 - 1
3a = 21
a = 7
Thus from eqn 1,
length = 1 + 2(7) = 1 + 14 = 15
Thus length of rectangle is 15 feet and width of rectangle is 7 feet
