Respuesta :

Let

width,w

length, l = 1.6w ...eqn 1

area, a = l × w ...eqn 2

subst for l in eqn 2

a = 1.6 w × w = 4000

4000 = 1.6 w^2

w^2 = 2500

w = 50

subst for w in eqn 1

l = 50 x 1.6 = 80

length = 80 yds

width = 50 yds