kayleahwilliams6 kayleahwilliams6
  • 01-02-2019
  • Mathematics
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Solve for x where 0 Equation: cot^2x+2cotx+1=0

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jdoe0001 jdoe0001
  • 01-02-2019

[tex]\bf \stackrel{\stackrel{notice~~ax^2+bx+c=0}{\downarrow }}{\underset{\textit{tis just a quadratic}}{cot^2(x)+2cot(x)+1=0}}\implies [cot(x)+1][cot(x)+1]=0 \\\\\\ cot(x)+1=0\implies cot(x)=-1\implies cot^{-1}[cot(x)]=cot^{-1}(-1) \\\\\\ x=cot^{-1}(-1)\implies x= \begin{cases} \stackrel{II~Quadrant}{\frac{3\pi }{4}}\\[1em] \stackrel{IV~Quadrant}{\frac{7\pi }{4}} \end{cases}[/tex]

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